Awarded as the best online publication by CIDC
This test is done to determine the water content in soil by oven drying method as per IS: 2720 (Part II) – 1973. The water content (w) of a soil sample is equal to the mass of water divided by the mass of solids.
Apparatus required :-
i) Thermostatically controlled oven maintained at a temperature of 110 ± 5oC
ii) Weighing balance, with an accuracy of 0.04% of the weight of the soil taken
iii) Air-tight container made of non-corrodible material with lid
iv) Tongs
PREPARATION OF SAMPLE
The soil specimen should be representative of the soil mass. The quantity of the specimen taken would depend upon the gradation and the maximum size of particles as under:
Procedure to determine Water Content In Soil By Oven Drying Method
i) Clean the container, dry it and weigh it with the lid (Weight ‘W1‘).
ii) Take the required quantity of the wet soil specimen in the container and weigh it with the lid (Weight ‘W2‘).
iii) Place the container, with its lid removed, in the oven till its weight becomes constant (Normally for 24hrs.).
iv) When the soil has dried, remove the container from the oven, using tongs.
v) Find the weight ‘W3‘ of the container with the lid and the dry soil sample.
If you have a query, you can ask a question here.
What i need to write for Conclusion.????
Why study of the moisture contain?
can u tel me what’s difference between oven tempreture for organic and inorganic soil
for organic- 60*celcius(beyond this CO2 form)
inorganic-(105-110)
Good test
Good analysis and explanation about soil test and ranges
Nice
Moisture content formula not making any sense. Percentage content should be mass of water divided by total mass. How is it that we use dry mass in the division? Mathematically, it’s not making sense.
yr right. Moisture content to be reported for the water % in original material wt, not on the dried material
Not wrong bro, here it’s not divided by total solid but total weight of soil solid( which is after removal of water)