Size of brick with Mortar = 20 cm × 10 cm × 10 cm
No. of bricks required per 1 m3 brickwork = 1 / (0.2 × 0.1 × 0.1) = 500 nos.
No. of bricks for 10 m3 brickwork = 500 × 10 = 5000 nos.
Size of brick without Mortar = 19 cm × 9 cm × 9 cm
Actual volume of 5000 bricks = 5000 × (0.19 × 0.09 × 0.09) = 5000 × 0.001539 = 7.695 m3
approx 7.7 m3
Volume of mortar = 10 – 7.7 = 2.3 m3
Adding 10% wastage = 2.3 + 2.3 × 10% = 2.53 m3
Adding 25% for dry mortar weight (Dry mortar weight > wet mortar weight)
Volume of dry mortar = 2.53 + 2.53 × 25% = 3.16 m3
approx 3.2 m3
Now,
For 1: 6 cement mortar,
Volume of cement = 3.2 / 7 = 0.45 m3
Volume of sand = 3.2 – 0.45 = 2.7 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.45 / 0.0347 = 12.97
approx 13 bags
Similarly,
For 1: 5 cement mortar,
Volume of cement = 3.2 / 6 = 0.53 m3
Volume of sand = 3.2 – 0.53 = 2.67 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.53 / 0.0347 = 15.27
approx 15 bags
For 1: 4 cement mortar,
Volume of cement = 3.2 / 5 = 0.64 m3
Volume of sand = 3.2 – 0.64 = 2.56 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.64 / 0.0347 = 18.44
approx 18 bags
For 1: 3 cement mortar,
Volume of cement = 3.2 / 4 = 0.8 m3
Volume of sand = 3.2 – 0.8 = 2.4 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.8 / 0.0347 = 23.05
approx 22.5 bags
For 1: 2 cement mortar,
Volume of cement = 3.2 / 3 = 1.07 m3
Volume of sand = 3.2 – 1.07= 2.13 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 1.07 / 0.0347 = 30.83
approx 30 bags
| Ratio | Cement | Sand |
| 1:2 | 1 m3 (30 bags) | 2 m3 |
| 1:3 | 0.75 m3 (22.5 bags) | 2.25 m3 |
| 1:4 | 0.6 m3 (18 bags) | 2.4 m3 |
| 1:5 | 0.5 m3 (15 bags) | 2.5 m3 |
| 1:6 | 0.45 m3 (13 bags) | 2.7 m3 |
As per standard values,
If you have a query, you can ask a question here.
Very good useful
I need more knowledge about the basic information in civil engineer work at field work site because I am fresh graduate
This formula assumes that all the faces of the brick are filled with mortar which isn’t true because the front and back faces of the brick are left for plastering
very simple way to explain everything needed…..thumbs up
Thanks, for the Very useful Information and Guide.
Actually, this is very important for the all Construction Workers.
Very Technical, and Useful. Thank You.
easily we can understand thanks
Thank you for guidance. Can you determine the motor requirements for all the sizes of the bricks. Will be very grateful.
Check the summary made for 10 cum of bricks,it’s not mentioned in summary,you have without quantity of bricks.
Nice too Meet you Too
Thanks